3-4
运行结果1
结果2
结果3
#includeint main(void){ double x,y; printf("Enter x:"); scanf("%lf",&x); if(x<0){ y=0; } else if(x<=15){ y=4*x/3; } else{ y=2.5*x-10.5; } printf("f(%.2f)=%.2f\n",x,y); return 0;}
3-5
#includeint main(void){ double value1,value2; char op; printf("Type in an expression:"); scanf("%lf%c%lf",&value1,&op,&value2); if(op=='+') printf("=%.2f\n",value1+value2); else if(op=='-') printf("=%.2f\n",value1-value2); else if(op=='*') printf("=%.2f\n",value1*value2); else if(op=='/') printf("=%.2f\n",value1/value2); else printf("Unknown operator\n"); return 0;}
3-7
#includeint main(void){ int digit,letter,other; char ch; int i; digit=letter=other=0; printf("Enter 10 characters:"); for(i=1;i<=10;i++){ ch=getchar(); if((ch>='a'&&ch<='z')||(ch>='A'&&ch<='Z')) letter++; else if(ch>='0'&&ch<='9') digit++; else other++; } printf("letter=%d,digit=%d,other=%d\n",letter,digit,other); return 0;}